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\frac{w+a}{d+3}=\frac{r}{t}



\frac{w+a}{d+3}=\frac{r}{t}
= \frac{\partial y}{\partial x}





tr

\int_{0}^{1}\frac{x^{4}\left(1-x\right)^{4}}{1+x^{2}}dx
=\frac{22}{7}-\pi

http://hello-ed.blogspot.com/2008/11/latex-for-blogger.html





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